Class XI

A particle of mass 10 g is executing simple harmonic motion with an amplitude of 0.5 m and periodic time of (pi/5 ) seconds. The maximum value of the force acting on the particle is
  1. 5 N
  2. 0.5 N
  3. 2.5 N
  4. 0.5 N
If x, F and V denote the displacement, force acting and the potential energy of a particle then
  1. V= Fx
  2. + dV/dx
  3. + dV/d
  4. -dV/dx
If the period of oscillation of mass M suspended from a spring is one second, then the period of mass 4 M will be
  1. 2s
  2. 1/ 4s
  3. 1/ 2s
  4. 4s
A particle is executing S.H.M with an amplitude of 4 cm and time period 12 sec. The time taken by the particle in going from its mean position to a position of displacement equal to 2 cm is T1T1..The time taken from this displaced position of 2 cm to reach the extreme position is T2. Therefore, T1T1/ T2T2 will be
  1. 41276.0
  2. 1/ 3
  3. 1
  4. 2
What is constant in simple harmonic motion?
  1. Potential energy
  2. Periodic time
  3. Restoring force
  4. Kinetic motion
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