Class XI The angular momentum L of the particle having a position vector and linear momentum , with respect to the origin O is defined to be L = × . ⃗ r⃗ p⃗ ω⃗ L = × ⃗ r⃗ p⃗ L = r⃗ ×p⃗ ×r⃗ L = × × ⃗ r⃗ r⃗ p⃗ For rolling motion without slipping the kinetic energy of the body is equal to the sum of kinetic energies of translation and rotation equal to the kinetic energy of translation equal to the difference of kinetic energies of translation and rotation equal to the difference of kinetic energies of translation and rotation The moment of inertia of a thin uniform ring of mass 1 Kg about an axis passing through the centre and perpendicular to the plane of the ring is 0.25 Kg m2m2.Then the diameter of the ring is 1 m 0.25 m 0.75 m 0.5 m Angular momentum of a body is defined as the product of Moment of inertia and angular velocity Linear velocity and angular velocity Mass and angular velocity Centripetal force and radius A spherical solid ball of 1 kg. mass and radius 3 cm is rotating about an axis passing through its centre with an angular velocity of 50 radians/s. The kinetic energy of rotation is 910 J 45000 J 920 J (9/20)J Do you really want to submit this quiz? Cancel Submit Quiz